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Two metal plates having a potential difference of 800 V are 0.02 m apart horizontally. A particle of mass 1.96 xx 10^(-15) kg is suspended in equilibrium between the plates. If e is the elementary charge, the charge on the particle is |
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Answer» Solution :For steady position weight = ELECTRIC force `therefore mg = QE` `therefore mg = "NE"E` `therefore "ne" = (mg)/E = (mgd)/V [therefore E =V/d]` `=(1.96 xx 10^(-15) xx 9.8 xx 0.02)/800 = 0.00048 xx 10^(-15)` `therefore Q = 3 xx 1.6 xx 10^(-19)` `therefore Q = 3e(therefore 1.6 xx 10^(-19) C =e)` |
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