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Two metallic oxides contain 27.6% and 30%oxygen respectively. If the formula of the first oxideis X3O4, that of the second will be(1) XO(3) XO5(2) XO2(4) X.O3 |
Answer» Given that, formula of first oxide = M3O4Let mass of the metal = x% of metal in M3O4= (3x/ 3x+64) *100but as given % age = (100-27.6) = 72.4 %so, (3x/ 3x+64)*100 = 72.4or x = 56.in 2nd oxide,oxygen = 30%....so metal = 70%so, the ratio isM : O70/56 : 30/161.25 : 1.8752 : 3so, 2nd oxide is M2O3 |
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