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Two metallic wires P_(1) & P_(2) ofthe same material & same length but different cross sectional areas A_(1) & A_(2) are joined together & connected to a source of emf. Find the emf of the drift velocities of free electrons in the two wires when they are connected in series. |
Answer» Solution :In SERIES the circuite remain the same. `:. I=- "NE" A_(1)v_(d_(1))= nA_(2)ev_(d_(2)) (or) (v_(d_(1)))/(v_(d_(2)))=(A_(2))/(A_(1))` |
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