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| 1. |
Two metals A and B have work function 4 eV and 10 eV respectively. Which metal has higherthershold wavelength ? |
| Answer» SOLUTION :`omega_0` = h`v_0 = (HC)/lambda_0` i.e., `lambda_0 prop 1/omega_0` So, metal A with LOWER function has higher threshold WAVELENGTH. | |