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Two metals A and B possess the same numberof electrons in L shell and they differ by 1 unit in the number of electrons present in valence shell and numberof valence electrons are greater in B than A. The ions formedget the configuration of the nearest inert gases namely argon and neon respectively. Give the probable electronic configurations ofmetals corresponding to A and B and give the formulae of their corresponding nitrite , nitrate , sulphite and bisulphite. |
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Answer» Solution :`{:("Shell",A,B),(L,8,8),("Electronic configuration","2,8,8,1","2,8,2"),("Metal",K,Mg),("FORMULAE",(i)""KNO_(2),Mg(NO_(2))_(2)),(,(II)""KNO_(3),Mg(NO_(3))_(2)),(,(iii)K_(2)SO_(3),MgSO_(3)),(,(iv)KHSO_(3),Mg(HSO_(3))_(2)):}` Or `{:(,,A,B,),("Electronic",,"2,8,8,2","2,8,3",),("Configuration",,,,),("Metal",,CA,Al,),("Formulae",(i),Ca(NO_(2))_(2),Al(NO_(2))_(2),),(,(ii),Ca(NO_(3))_(2),AL(NO_(3))_(3),),(,(iii),CaSO_(3),Al_(2)(SO_(3))_(3),),(,(iv),Ca(HSO_(3))_(2),Al(HSO_(3))_(3),):}` |
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