InterviewSolution
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InterviewSolution
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Two moles of a gas expand isothermally at 300 K. If the initial volume of the gas is 23 L and the final volume is 46 L, find the work done by the gas on its surroundings. (R = 8.314 J/mol.K) |
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Answer» Data ; n = 2, T = 300 K, V, = 23 L = 23 × 10-3 m3 , Vf = 46 L = 46 × 10-3 m3 , R = 8.314 J/mol .K The work done by the gas on its surroundings, W = nRT ln \((\frac{V_f}{V_i})\) = 2.303 nRT log10 \((\frac{V_f}{V_i})\) = (2.303) (2) (8.314) (300) log10 \((\frac{46\times10^{-3}}{23\times10^{-3}})\) = (4.606) (8.314) (300) log102 = (4.606) (8.314) (300) (0.3010) = 3458J |
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