InterviewSolution
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InterviewSolution
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Two moles of ammonia is introduced in a evacuated500 mL vessel at high temperature. Thedecomposition reaction is:2NH,(g)N2(g)+3H2(g)At the equilibrium NH, becomes 1 mole then the Kwould be:-(A) 0.42(B) 6.75 |
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Answer» you have given initial [NH3]. If [NH3] remaining = 1 mole/L, then 1mole/L reacted2NH3(g) N2(g)+3H2(g). So change in concentration of NH3 = -1 mole/L. This means that because 2 mole NH3 make 1 mole of N2, the change in [N2] will +0.5mol/L and that for H2 will be +1.5mol/L. and equilibrium concentration of NH3 will be 1 mole/LPlug into Keq= [N2][H2}^3/[NH3]^2 and find Keq=(1.5^3)(0.5) = 1.687 nearly equal to 1.7 but given answer is B |
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