InterviewSolution
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InterviewSolution
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Two moles of an ideal monoatomic gas occupy a volume 2V at temperature 300K, it expands to a volume 4V adiabatically, then the final temperature of gas isA. 179 KB. 189 KC. 199 KD. 219 K |
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Answer» Correct Answer - B Since in an adiabatic process `T_(1)V_(1)^(gamma-1)=T_(2)V_(2)^(gamma-1)` `T_(2)=T_(1)(V_(1))/(V_(2))^(gamma-1)=300((2V)/(4V))^((5)/(3)-1))` `=300((1)/(2)^(2//3)=(300)/(2^(2//3))=188.98 = 189 K` |
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