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Two moles of helium gas are taken over the cycle ABCDA, as shown in the P-T diagram The net work done on the gas in the cycle ABCDA is :A. `1076R`B. `1904R`C. ZeroD. `276R` |
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Answer» Correct Answer - D `W_(ABCDA) = W_(AB) + W_(DC) + W_(CD) + W_(DC)` =`muR(500-300) + 2.303muR(500)"log"(2)/(2) + muR(300-500) + 2.303muR(300)"log"(1)/(2) = 276R` Work done on the gas = `-276R` |
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