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Two monochromatic beam A and B of equal intensity I,hit a screen.The number of photons hitting the screen by beam A is twice that by beam B.Then what inference can you make about their frequencies? |
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Answer» SOLUTION :Intensity of light is given by, `I=(E_(N))/(At)=(NHF)/(At)` (Where A=area of given screen) `therefore I=m.hf` where n.=`(n)/(At)`=no. of photon INCIDENT of unit unit area of screen per unit TIME `therefore n.f=(I)/(h)`=constant(`because` Here I is constant) `therefore n._(A)f_(A)=n._(B)f_(B)` (As per the statement) `therefore f_(A)=(f_(B))/(2)` `implies` Frequency of beam A would be half of frequency of beam B. |
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