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Two monochromatic radiations of frequencies v_(1) and v_(2) (v_(1) gt v_(2)) and having the same intensity are, in turn, incident on a photosensitive surface to cause photoelectric emission. Explain, giving reason, in which case (i) more number of electrons will be emitted and (ii) the maximum kinetic energy of the emitted photoelectrons will be more. |
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Answer» Solution :(i) Number of electrons EMITTED DEPENDS on intensity of radiation falling on it. Since `v_(1)` and `v_(2)` frequencies have same intensity, therefore same number of electrons will be emitted by both. (II) `hv=phi_(0)+K_("max")` `:.` For given `phi_(0)` (work function of metal) `K_("max")` increases with v `:.` MAXIMUM KINETIC energy of emitted photoelectrons will be more for monochromatic light of frequency `v_(1)` (as `v_(1) gt v_(2)`). |
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