1.

Two moving coil meters, `M_(1) and M_(2)` have the following particulars : `R_(1)=10 Omega, n_(1)=30`, `A_(1)=3.6xx10^(-3)m^(2), B_(1)=0.25 T` `R_(2)=14 Omega, n_(2)=42` `A_(2)=1.8xx10^(-3)m^(2), B_(2)=0.50 T` (The spring constants are identical for the two meters). Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of `M_(2) and M_(1)`.

Answer» Given, `R_(1)=10 Omega, N_(1)=30, A_(1)=3.6xx10^(-3)m^(2), B_(1)=0.25 T`
`R_(2)=14 Omega, n_(2)=42, A_(2)=1.8xx10^(-3)m^(-2), B_(2)=0.50 T, K_(1)=K_(2)`
a) `I=(NAB)/(K)`
`(I_(s2))/(I_(s1))=(N_(2)B_(2)A_(2)K_(1))/(N_(1)B_(1)A_(1)K_(2))=(42xx0.50xx1.8xx10^(-3))/(30xx0.25xx3.6xx10^(-3))=1.4`
b) `V=(NAB)/(KR)`
`(V_(s2))/(V_(s1))=(N_(2)B_(2)A_(2). K_(1)R_(1))/(N_(1)B_(1)A_(1).K_(2)R_(2))=(42xx0.50xx1.8xx10^(-3)xxKxx10)/(Kxx14xx30xx0.25xx3.6xx10^(-3))=1`


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