1.

Two mutually perpendicular wire carry charge densities lambda_1 and lambda_2. The electric lines of force makes angle alpha with second wire, then lambda_1//lambda_2 is

Answer»

`TAN^(2)alpha`
`COT^2 alpha`
`sin^2 alpha`
`cos ^2alpha`

Solution :`E_(1)=(lambda_(1))/(2piepsilon_(0)x)` and `E_(1)=(lambda_(q))/(2piepsilon_(0)y)`
`(E_(1))/(E_(2))=((lambda_(1))/(lambda_(2)))((y)/(x))`
`(1)/(tanalpha)=((lambda_(1))/(lambda_(2)))tanalpha` or `(lambda_(1))/(lambda_(2))=cot^(2)alpha`


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