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Two nuclei have their mass numbers in the ratio of 1:3. The ratio of their nuclear densities would be |
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Answer» `(3)^(1//3):1` Their RADII will be in the ratio `R_0A_1^(1//3) : R_0A_2^(1//3)=1:3^(1//3)` DENSITY,`rho=A/(4/3piR^3)` `THEREFORE rho_(A_1):rho_(A_2)=1/(4/3 piR_0^3. 1^3):3/(4/3piR_0^3(3^(1//3))^3)=1:1` Their nuclear densities will be the same . |
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