Two nuclei have their mass numbers in the ratio of `1:3`. The ratio of their nuclear densities would beA. `(3)^(1//3):1`B. `1:1`C. `1:3`D. `3:1`

Two nuclei have their mass numbers in the ratio of `1:3`. The ratio of

1.	Two nuclei have their mass numbers in the ratio of `1:3`. The ratio of their nuclear densities would beA. `(3)^(1//3):1`B. `1:1`C. `1:3`D. `3:1`
Answer» Correct Answer - B `R=R_(0).A^(1//3)` So nuclear density `=(A.m)/(v)` m = mass of each nucleon, A = mass number `=(3m)/(4piR_(0)^(3))=" independent of A."`

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Two nuclei have their mass numbers in the ratio of `1:3`. The ratio of their nuclear densities would beA. `(3)^(1//3):1`B. `1:1`C. `1:3`D. `3:1`

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