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Two nuclei P and Q have equal number of atoms at t=0. Their half lives are 3 hrs and 9 hrs respectively. Compare their rates of disintegration after 18 hours form the starts. |
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Answer» Correct Answer - `3:16` Number of half lives of P in 18 hours `=18/3=6` Number of half lives of Q in 18 hours `=18/9=2` Therefore, no. of nuclei left undecayed: `N_(1)=N_(0)(1/2)^(6)=N_(0)//64` `N_(2)=N_(0)(1/2)^(2)=N_(0)//4` The ratio of their rates of disintegration is `(R_(1))/(R_(2))=(lambda_(1)N_(1))/(lambda_(2)N_(2))=(T_(2))/(T_(1))((N_(1))/(N_(2)))=9/3xx(N_(0)//64)/(N_(0)//4)=3/16` `3:16` |
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