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two numbers are in the ratio 5:6.if 8 is subracted from each of the numbers the ratio becomes 4:5.find the numbers? |
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Answer» Answer: Step-by-step explanation: Answer: Let us consider the two numbers are x and y Given: x/y = 5/6 x × 6 = y × 5 6x – 5Y = 0………………..(1) If 8 is SUBTRACTED from each of the numbers then the ratio is 4:5. \(\FRAC{x-8}{y-8}= \frac{4}{5}\) ⇒ 5x – 40 = 4y – 32 Then the equation is 5x – 4y = 8……………….(2) From equation (1) x = 5y/6 Substituting value of x in equation (2) 5(5y/6) – 4y = 8 y = 48 Substitute the value of y in equation (1) we get 6x – 5(48) = 0 6x = 240 x = 40 Therefore the numbers are 40 and 48. |
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