Two objects A and B of equal mass are suspended from two springs constants `k_(A)` and `k_(B)` if the objects oscillate vertically in such a manner that their maximum kinetic energies are equal, then the ratio of their amplitudes isA. `(K_(B))/(K_(A))`B. `sqrt((K_(B))/(K_(A)))`C. `(K_(A))/(K_(B))`D. `sqrt((K_(A))/(K_(B)))`

Two objects A and B of equal mass are suspended from two springs const

1.	Two objects A and B of equal mass are suspended from two springs constants `k_(A)` and `k_(B)` if the objects oscillate vertically in such a manner that their maximum kinetic energies are equal, then the ratio of their amplitudes isA. `(K_(B))/(K_(A))`B. `sqrt((K_(B))/(K_(A)))`C. `(K_(A))/(K_(B))`D. `sqrt((K_(A))/(K_(B)))`
Answer» Correct Answer - B Kinetic energy of A =Kinetic energy of B `1/2 K_(A)a^(2)=1/2 K_(B)b^(2)` So ratio of amplitude `=sqrt((K_(B))/(K_(A)))`

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