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Two open pipes of length L are vibrated simultaneously. If length of one of the pipes is reduced by y. then the number of beats heats per second will be if the velocity of sound is v and `y lt lt L` :-A. `(vy)/(2L^(2))`B. `(vy)/(L^(2))`C. `(vy)/(2L)`D. `(2L^(2))/(vy)` |
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Answer» Correct Answer - A `lamda_(1)=2L,lamda_(2)=2(L-y)` `Delta f=f_(2)-f_(1)=(v)/(lamda_(2))-(v)/(lamda_(1))=(v)/(2)[(1)/(L-y)-(1)/(L)]` `rArr (vy)/(2(L-y)L)=(vy)/(2L^(2))` |
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