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Two parallel plate capacitors X and Y have the same area of plates and same separation between them , X has air between the plates while Y contains a dielectric medium of epsi_(r) = 4. Calculate capacitance of each capacitor if equivalent capacitance of the combination is 4 mu F . |
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Answer» Solution :Here `A_(X) = A_(Y) , d_(X) = d_(Y) , (epsi_(R))_(X) = 1` and `(epsi_(r))_(Y) = 4` `therefore (C_(X))/(C_(Y)) = ((epsi_(r))_(X))/((epsi_(r))_(Y)) = (1)/(4) IMPLIES C_(Y) = 4 C_(X)` As capacitors X and Y have been joined in SERIES and their equivalent capacitance is `4 mu F` , hence `(1)/(4 mu F) = (1)/(C_(X)) + (1)/(C_Y) = (1)/(C_X) + (1)/(4 C_(X)) = (5)/(4 C_X) implies C_X = (4 xx 5)/(4) mu F ` and `C_(Y) = 4 C_(X) = 20 mu F ` |
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