1.

Two particle A and B are in motion. If the wavelength associated with 'A' is 33.33 nm, the wavelength associated with 'B' whose momentum is 1//3^(rd) of 'A' is

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`1.0 xx 10^(-8)` m
`2.5 xx 10^(-8)` m
`1.25 xx 10^(-7)` m
`1.0 xx 10^(-7)` m

Solution :(d): `lamda_(A) =33.3` nm = `33.33 xx 10^(-9)` m
`lamda_(A) = H//p_(A)`...(i)
`lamda_(B) = (h)/(p_(A)//3) = (3h)/(p_(A))`...(II)
From eq (i) and (ii), we get
`(lamda_(A))/(lamda_(B)) = 1/3 RARR lamda_(B) = 33.33 xx 10^(-9) xx 3 =99.99 xx 10^(-9)` m
`~~ 1.0xx10^(-7)` m


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