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Two particle execute `SHM` with amplitude `A` and `2A` and angular frequency `omega` and `2omega` repectively. At `t=0` they starts with some initial phase difference. At, `t=(2pi)/(3omega)`. They are in same phase. Their initial phase difference is-A. `(pi)/(3)`B. `(2pi)/(3)`C. `(4pi)/(3)`D. `pi` |
Answer» Correct Answer - B::C | |