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Two particlemove in a unifrom gravitational field withan acceleration"g". Atthe initial momentthe paricleswere locatedat onepointand movedwithvelcoities u_(1) = 3.0 ms^(-1) and u_(2) = 4.0 ms^(-1) horizontally in opposite directions. Find the distancebetweenthe patricles at the momentwhentheirtheir velocityvectors become mutually perpendicular . |
Answer» SOLUTION :`t= sqrt((u_(1)u_(2))/g), x=(u_(1) + u_(2))t` ![]() =0.48 m |
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