1.

Two particles A_(1) and A_(2) masses m_(1),m_(2)(m_(1)gtm_(2)) have the same de-Broglie wavelegth .Then

Answer»

their MOMENTA are the same
their energies are the same
energy of `A_(1)` is less the energy of `A_(2)`
energy of `A_(1)` is more than the energy of `A_(2)`

Solution :ACCORDING to formula `p=(h)/(lambda)`,since here `lambda` is same,p also WOULD be same.Hence ,option (A) is correct.
Energy of a particle ,`E=(p^(2))/(2m)impliesEprop(1)/(m)`
(`because` p is same )
`impliesE_(1)ltE_(2)(because m_(1)gtm_(2))`
`impliesE_(A_(1))ltE_(A_(2))`


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