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Two particles A and B are connected by a rigid rod AB. The rod slides along perpendicular rails as shown. The velocity of A to the left is 10 ms^(-1) What is the velocity of B when anglealpha=60^(@)? |
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Answer» 9.8 m`s^(-1)` Speed of `B =dy//dt` Now `x^(2)+y^(2)=(AB)^(2)` Diff. w.r.t. t  `2x(dx)/(dt)+2ydy//dt=0` or`(dy)/(dt) =- (x)/(y)(dx)/(dt)= - cot 60^(@)xx10 = - 5.8 ms^(-1)` |
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