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    				| 1. | Two particles A and B are placed as shown in figure. The particle A, on the top of tower, is projected horizontally with a velocity u and particle B is projected along the surface towards the tower, simultaneously. If both particles meet each other, then the speed of projection of particles B is [ignore any friction] A. `dsqrt(g/(2H)) - u`B. `d sqrt(g/(2H))`C. `dsqrt(g/(2H))+u`D. u | 
| Answer» Correct Answer - A a. Time taken by particles to collide `t = sqrt((2H)/(g))` Then `u sqrt((2H)/(g))+Vsqrt((2H)/g) = d` `rArr u + V = d sqrt(g/(2H)) or v = d sqrt(g/(2H)) - u `. | |