Two particles A and B execute simple harmonic motions of period T and `5T//4`. They start from mean position. The phase difference between them when the particle A complete an oscillation will beA. `pi//2`B. `0`C. `2pi//5`D. `pi//4`

Two particles A and B execute simple harmonic motions of period T and

1.	Two particles A and B execute simple harmonic motions of period T and `5T//4`. They start from mean position. The phase difference between them when the particle A complete an oscillation will beA. `pi//2`B. `0`C. `2pi//5`D. `pi//4`
Answer» Correct Answer - C `x_A=Asin((2pi)/(T_1)t)`, `x_B=Asin((2pi)/(T_2))t` Phase difference `\|phi\|=((2pi)/(T_1)-(2pi)/(T_2))t` At `t=T`, `\|phi\|=((2pi)/(T)-(2pi)/(5T//4))T` `=2pi(1-4/5)=(2pi)/(5)`

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Two particles A and B execute simple harmonic motions of period T and `5T//4`. They start from mean position. The phase difference between them when the particle A complete an oscillation will beA. `pi//2`B. `0`C. `2pi//5`D. `pi//4`

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