1.

Two particles A and B of equal masses are suspended from two massless springs of spring constants k_(1) and k_(2), respectively, If the maximum velocities, during oscillation, are equal, the ratio of amplitude of A and B is

Answer»

`SQRT((k_(1))/(k_(2)))`
`(k_(2))/(k_(1))`
`sqrt((k_(2))/(k_(1)))`
`(k_(1))/(k_(2))`

SOLUTION :Maximum velocity during SHM = `A omega`
But `K=m omega^(2)`
`:.""omega=sqrt((k)/(m))"":." Maximum velocity "A sqrt((k)/(m))`
Here the maximum velocity is same and m is also same
`:.""A_(1)sqrt(k_(1))=A_(2)sqrt(k_(2))"":.(A_(1))/(A_(2))=sqrt((k_(2))/(k_(1)))`


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