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Two particles A and B of masses m and 2m have charges q and 2q respectively. Both these particle moving with velocities v_1 and v_2 respectively in the same directionenter the same magnetic field B acting normally to their direction of motion. If the two force F_A and F_B acting on them are in the ratio 1:2 , find the ratio of their velocities. |
| Answer» SOLUTION :As FORCE `F = qvB`, hence `(F_A)/(F_B) = 1/2 = (q_A v_A B)/(q_B v_B B) = (qv_A)/(2qv_B) = (v_A)/(2v_B) implies v_A = v_B` | |