Two particles are executing simple harmonic motion. At an instant of time t their displacement are y_(1)=a cos(omegat) and""y_(2)=a sin(omegat) Then the phase difference between y_(1) and y_(2) is:

Two particles are executing simple harmonic motion. At an instant of t

1.	Two particles are executing simple harmonic motion. At an instant of time t their displacement are y_(1)=a cos(omegat) and""y_(2)=a sin(omegat) Then the phase difference between y_(1) and y_(2) is:
Answer» `120^(@)` `90^(@)` `180^(@)` zero. Solution :`y_(1)=a cos omega t=a sin(omega t+pi//2)` `y_(2)=a sin omegat`. `:.` Phase difference between `y_(1)` and `y_(2)` is `90^(@)` Correct CHOICE is (a).

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Two particles are executing simple harmonic motion. At an instant of time t their displacement are y_(1)=a cos(omegat) and""y_(2)=a sin(omegat) Then the phase difference between y_(1) and y_(2) is:

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