Two particles are projected with same initial velocity one makes angle `theta` with horizontal while other makes an angle `theta` with vertical. If their common range is R then product of their time of flight is directly proportional to :A. RB. `R^2`C. `1/R`D. `R^0`

Two particles are projected with same initial velocity one makes angle

1.	Two particles are projected with same initial velocity one makes angle `theta` with horizontal while other makes an angle `theta` with vertical. If their common range is R then product of their time of flight is directly proportional to :A. RB. `R^2`C. `1/R`D. `R^0`
Answer» Correct Answer - A `R=(u^2sin2theta)/(g), t_1=(2usintheta)/(g)` `t_2 = (2usin(90^@-theta))/(g)=(2ucostheta)/(g)` `therefore" " t_1t_2=(4u^2sinthetacostheta)/(g)=(2R)/(g)` `or" "t_1t_2propR`

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Two particles are projected with same initial velocity one makes angle `theta` with horizontal while other makes an angle `theta` with vertical. If their common range is R then product of their time of flight is directly proportional to :A. RB. `R^2`C. `1/R`D. `R^0`

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