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Two particles, carrying charges -q and +q and having equal masses m each, are fixed at the rod is clamped at an end and is placed in a uniform electric field E with the axis of the dipole along the electric field. The rod is slightly tlted and then released. Neglecting gravity find the time period of small oscillations. |
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Answer» Solution :Consider the ROD to be a SIMPLE PENDULUM For simple pendulum ` T=2pisqrt(l/g) ` ` (l=length,g=accln) ` Now force experienced by the charges ` F=EQ ` Now, `accln =F/m=(Eq)/m ` Here,`length =a ` So, time periode ` T=2pisqrt((ma)/(qE))` |
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