Saved Bookmarks
| 1. |
Two particles move in a uniform gravitational field with an acceleration "g". Al the initial moment the particles were located at same point and moved with velocities u_(1)=0.8 ms^(-1) and u_(2)=4.0 ms^(-1) horizontally in opposite directions. Find the distance between the particles at the moment when their velocity vectors become mutually perpendicular. (g=10 ms^(-2)) |
Answer» Solution :`t= SQRT((u_(1)u_(2))/(G)),x=(u_(1)=u_(2))t` 
|
|