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Two particles move toward each other with velocities v_1=0.50c and v_2=0.75c relative to a laboratory frame of reference. Find: (a) the approach velocity of the particles in the laboratory frame of reference, (b) their relative velocity. |
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Answer» Solution :(a) By DEFINITION the velocity of approach is `v_(approach)=(dx_1)/(dt)-(dx_2)/(dt)=v_1-(-v_2)=v_1+v_2` in the reference frame K. (B) The relative velocity is obtained by the transformation law `v_r=(v_1-(-v_2))/(1-(v_1(-v_2))/(c^2))=(v_1+v_2)/(1+(v_1v_2)/(c^2))` |
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