Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.A. `v=1/(2R)sqrt((1/(Gm)))`B. ` v=sqrt(((Gm)/(2R)))`C. `v=1/2sqrt(((Gm)/R))`D. `v=sqrt(((4Gm)/R))`

Two particles of equal mass go around a circle of radius R under the a

1.	Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.A. `v=1/(2R)sqrt((1/(Gm)))`B. ` v=sqrt(((Gm)/(2R)))`C. `v=1/2sqrt(((Gm)/R))`D. `v=sqrt(((4Gm)/R))`
Answer» Correct Answer - C `F_(G)=(Gm^(2))/(4R^(2))implies(Mv^(2))/R(Gm^(2))/(4R^(2))` `:. v=1/2sqrt((GM)/R`

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Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.A. `v=1/(2R)sqrt((1/(Gm)))`B. ` v=sqrt(((Gm)/(2R)))`C. `v=1/2sqrt(((Gm)/R))`D. `v=sqrt(((4Gm)/R))`

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