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Two particles of equal mass m and charge t are placed at a distance 16 cm. They do no experience any force. The value of q/m is……..

Answer»

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`sqrt(4piepsilon_(0)G)`
`sqrt((piepsilon_(0))/G)`
`sqrt((G)/(4piepsilon_(0))`

Solution :WEIGHT =Coulomb force
`(Gm^(2))/(16 xx 10^(-2))^(2) = (KQ^(2))/(16 xx 10^(-2))^(2)`
`THEREFORE q/m = sqrt(G/K) = sqrt(4piepsilon_(0)G) [therefore k =1/(4piepsilon_(0))]`


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