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Two particles of mass m_(1) and m_(2), approach each other due to their mutual gravitational attraction only. Then |
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Answer» acceleration of both the particles are equal. `F=(Gm_(1)m_(2))/(r^(2))` Acceleration of particle of mass `m_(1)a_(1)(F)/(m_(1))=(Gm_(2))/(r_(2))` `:. a_(1) PROP m_(2)`. |
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