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Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50 cm. Assuming that the only forces acting on the particles are their mutual gravitation find the initial acceleration of the two particles. |
Answer» Correct Answer - A::B::C `a_(1) = (F)/(m_(1)) = (Gm_(1)m_(2))/(r^(2)) = (Gm_(2))/(r^(2))` `=((6.67 xx 10^(-11))(2))/((0.5)^(2))` `= 5.3 xx 10^(-10) m//s^(2)` Similarly, `a_(2) = (Gm_(1))/(r^(2))` |
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