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Two particles of masses 1 kg and 2 kg are placed at a separation of 50 cm find out gravitational force between themA. `5.3x10^(-10) N`B. `4.9xx10^(-9) N`C. `6.5xx10^(-8) N`D. `6.9xxx10^(-7) N` |
Answer» Given `M_(1)=1 kg, M_(2)=2 kg` and r=50 cm `=1/2M` `therefore` Gravitational force `F=(GM_(1)M_(2))/(r^(2))=(6.67xx10^(11)xx1xx2)/(1/2)^(2)=5.3xx10^(-10)N` |
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