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Two particles of masses `1kg` and `2kg` are placed at a distance of `50cm`. Find the initial acceleration of the first particle due to gravitational force. |
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Answer» Gravitational force between two particles `F=(Gm_(1)m_(2))/(r^(2))=(6.67xx10^(-11)xx1xx2)/((0.5)^(2))=5.3xx10^(-10)N` The acceleration of `1Kg` particles is `a_(1)=F/(m_(1))=(5.3xx10^(-10))/1=5.3xx10^(-10)ms^(-2)` towards the `2Kg` mass |
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