InterviewSolution
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InterviewSolution
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Two particles of masses `m_(1)` and `m_(2)` initially at rest a infinite distance from each other, move under the action of mutual gravitational pull. Show that at any instant therir relative velocity of approach is `sqrt(2G(m_(1)+m_(2))//R)` where `R` is their separation at that instant.A. `sqrt((G(m_(1)+m_(2)))/(r))`B. `sqrt((2G(m_(1)+m_(2)))/(r))`C. `sqrt((Gm_(1)m_(2))/((m_(1)+m_(2))r))`D. `sqrt((G(m_(1)+m_(2)))/(2r))` |
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Answer» Correct Answer - B |
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