InterviewSolution
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InterviewSolution
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Two particles of masses `m_(1),m_(2)` move with initial velocities `u_(1)` and `u_(2)`. On collision, one of the particles get excited to higher level, after absording enegry. If final velocities of particles be `v_(1)` and `v_(2)` then we must haveA. `m_(1)u_(1)^(2) + m_(2)u_(2)^(2)-epsilon = m_(1)upsilon_(1)^(2) + m_(2)upsilon_(2)^(2)`B. `(1)/(2)m_(1)u_(1)^(2) + (1)/(2)m_(2)u_(2)^(2) = (1)/(2)m_(1)upsilon_(1)^(2) + (1)/(2)m_(2)upsilon_(2)^(2) - epsilon`sC. `(1)/(2)m_(1)u_(1)^(2) + (1)/(2)m_(2)u_(2)^(2) -epsilon = (1)/(2)m_(1)upsilon_(1)^(2) + (1)/(2)m_(2)upsilon_(2)^(2)`D. `(1)/(2)m_(1)^(2)u_(1)^(2) + (1)/(2)m_(2)^(2)u_(2)^(2) + epsilon = (1)/(2)m_(1)^(2)upsilon_(1)^(2) + (1)/(2)m_(2)^(2)upsilon_(2)^(2)` |
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Answer» Correct Answer - C `KE_("Before collision") = (1)/(2)m_(1)u_(1)^(2) + (1)/(2)m_(2)u_(2)^(2)` `KE_("After collision") = (1)/(2)m_(1) upsilon_(1)^(2) + (1)/(2)m_(2)upsilon_(2)^(2)` ` = (1)/(2)m_(1)u_(1)^(2) + (1)/(2)m_(2)u_(2)^(2) - epsilon` `KE_("Before collision") = KE_("After collision")` `(1)/(2)m_(1)u_(1)^(2) + (1)/(2)m_(2)u_(2)^(2) - epsilon = (1)/(2)m_(1)upsilon_(1)^(2) + (1)/(2)m_(2)upsilon_(2)^(2)` |
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