1.

Two particles P and Q describe coplanar concentric circles of radii a and a' with angular velocities omega andomega', (in the same sense ) respectively. If the angular velocity of P with respect to Q is x, then fill (49x)/(12) in OMR sheet. Take theta = (2pi)/(3), a = 2m, a' = 1m, omega = 2 "rad/s&" omega' = 1 "rad/s".

Answer»

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Solution :Let angle OPQ and PQO are a and b respectively when angle POQ `= theta`. As the particles P and Q move with constant angular speeds in their respectively CIRCLES, the velocity of point P and Q are
`V_(P) = a_(w)` and `V_(Q) = a' omega'` respectively
Now the angluar velocity of P relative to Q is
`omega_(r ) = (a omega cos d + a' omega' cos beta)/(d)`
`= (a omega [(a^(2) + d^(2) - a^('2))/(2AD)] + a' omega' [(a^('2) + d^(2) - a^(2))/(2a'd)])/(d)`

`= ((omega + omega'))/(2) + ((omega + omega') (a^(2) - a^('2)))/(2 (s^(2) + a^('2) - 2 a a' cos theta))`
If `omega_(r ) = 0` then`cos theta = (a^(2) omega + a^('2) omega')/(2a a' (omega + omega))`


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