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Two pendulum of lengths `1m` and `16m` are in phase at the mean position at a certain instant of time. If T is the time period of the shorter pendulum, then the minimum time after which they will again be in phase isA. `T/3`B. `(2T)/(3)`C. `(4T)/(3)`D. `(8T)/(3)` |
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Answer» Correct Answer - C `T_1=2pisqrt(1/g)=T`, `T_2=2pisqrt((16)/(g))=4T` `(omega_1-omega_2)t=2pi` `((2pi)/(T)-(2pi)/(4T))t=2pi` `t=(4T)/(3)` |
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