Two pendulums differ in lengths by `22m`. They oscillate at the same place so that one of then makes 30 oscillations and the other makes 36 oscillations during the same time. The length `(` in `cm)` of the pendulum are `:`

Two pendulums differ in lengths by `22m`. They oscillate at the same p

1.	Two pendulums differ in lengths by `22m`. They oscillate at the same place so that one of then makes 30 oscillations and the other makes 36 oscillations during the same time. The length `(` in `cm)` of the pendulum are `:`
Answer» `30xx2pisqrt((l_(1))/(g))=36xx2pisqrt((l_(2))/(g)) "or " (l_(1))/(l_(2))=(36xx36)/(30xx30)=(36)/(25)` Also, `l_(1)-l_(2)=22 cm (l_(1))/(l_(2))-1=(22)/(l_(2))` or `(22)/(l_(2))=(26)/(25)-1 " or "(l_(2))/(22)=(25)/(11) " or "l_(2)=50 cm,` `l_(1)=22+l_(2)=(22+50)cm=72 cm`

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Two pendulums differ in lengths by `22m`. They oscillate at the same place so that one of then makes 30 oscillations and the other makes 36 oscillations during the same time. The length `(` in `cm)` of the pendulum are `:`

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