1.

Two pendulums have timeperiods T and (5T)/(4). They start swinging in S.H.M. together. What will be the phase difference between them after the longer has completed one oscillation ?

Answer»

`45^(@)`
`90^(@)`
`60^(@)`
`30^(@)`

SOLUTION :No. of vibrations completed by shorter pendulum during the TIME bigger pendulumcompletes one vibration is `N=((5T)/(4))/(T)=(5)/(4)`
`:.` Diff. in vibrations `=(5)/(4)-1=(1)/(4)`.
`:.` Phasedifference `=(1)/(4)xx2pi=(pi)/(2)=90^(@)`.
THUS correctchoice is (b).


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