Two peojectiles are fired from the same point with same velocity at angles alpha and beta with the horizontal. They are aimed at a target distant, R from the point of projection. One falls a distance x short of R while other a distance y beyond R. If theta is the correct angle of projection then

Two peojectiles are fired from the same point with same velocity at an

1.	Two peojectiles are fired from the same point with same velocity at angles alpha and beta with the horizontal. They are aimed at a target distant, R from the point of projection. One falls a distance x short of R while other a distance y beyond R. If theta is the correct angle of projection then
Answer» `THETA = sin^(-1)[("xsin"2ALPHA+"ysin 2" beta)/(x+y)]` `theta =1/2 sin^(-1)[("xsin"2beta+"ysin 2" alpha)/(x+y)]` `theta =sin^(-1)[("xsin"2beta+"ysin 2" alpha)/(x+y)]` `theta =1/2 sin^(-1)[("xsin"2alpha+"ysin 2" beta)/(x+y)]` ANSWER :B

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Two peojectiles are fired from the same point with same velocity at angles alpha and beta with the horizontal. They are aimed at a target distant, R from the point of projection. One falls a distance x short of R while other a distance y beyond R. If theta is the correct angle of projection then

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