1.

Two pieces of wire A and B of the same material have their lengths in the ratio 1 : 2 and their diameters in the ratio 2 : 1 if they are stretched by same force. Their elongation will be in the ratio of :

Answer»

`1:8`
`8:1`
`2:1`
`1:4`

SOLUTION :`Deltal=F/Y.L/A=F/YL/((piD^(2))/4)=(4FL)/(piYD^(2))`
`THEREFORE(Deltal_(1))/(Deltal_(2))=(L_(1))/(L_(2))XX((D_(2))/(D_(1)))^(2)`
`=1/2xx(1/2)^(2)=1/8`
Thus correct CHOICE is (a).


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