Saved Bookmarks
| 1. |
Two pith balls of mass 10mg each are suspended by two threads from the samesupport are charged identically. They move apart by 0.08m and threads make an angle 60^@with each other. Find the charge on each pith ball |
Answer» SOLUTION : In the fig `F = T SIN 30^@ `…(1) `MG = T cos 30^@`…(2) equation `1/2 RARR (F)/(mg) = tan 30^@` ` F = mg tan 30^@` `(1)/(4pi epsi_0) (Q^2)/(r^2) = mg tan 30^@` `9 xx 10^9 xx (q^2)/(r^2) = 10 xx 10^(-6) xx 9.8 xx 0.5773` `9 xx 10^9 xx (q^2)/((0.08)^2) = 56.58 xx 10^(-6)` `q^2 = 0.0402 xx 10^(-15)` ` q^2 = 40.2 xx 10^(-18)` `q = 6.34 nC` |
|