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Two planets `A` and `B` have the same material density. If the radius of `A` is twice that of `B`, then the ratio of the escape velocity `(v_(A))/(v_(B))` isA. `2`B. `sqrt(2)`C. `1//sqrt(2)`D. `1//2` |
Answer» Correct Answer - a `V_(e)=sqrt((2GM)/R)impliesV_(e)=sqrt((2G.4/3piR^(3)rho)/R)` `V_(e)=sqrt(8Gpirho)R` `(V_(A))/(V_(B))=(R_(A))/(R_(B))implies(V_(A))/(V_(B))=2/1` |
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